(5x^4-2x^2+2)=

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Solution for (5x^4-2x^2+2)= equation:


Simplifying
(5x4 + -2x2 + 2) = 0

Reorder the terms:
(2 + -2x2 + 5x4) = 0

Remove parenthesis around (2 + -2x2 + 5x4)
2 + -2x2 + 5x4 = 0

Solving
2 + -2x2 + 5x4 = 0

Solving for variable 'x'.

Begin completing the square.  Divide all terms by
5 the coefficient of the squared term: 

Divide each side by '5'.
0.4 + -0.4x2 + x4 = 0

Move the constant term to the right:

Add '-0.4' to each side of the equation.
0.4 + -0.4x2 + -0.4 + x4 = 0 + -0.4

Reorder the terms:
0.4 + -0.4 + -0.4x2 + x4 = 0 + -0.4

Combine like terms: 0.4 + -0.4 = 0.0
0.0 + -0.4x2 + x4 = 0 + -0.4
-0.4x2 + x4 = 0 + -0.4

Combine like terms: 0 + -0.4 = -0.4
-0.4x2 + x4 = -0.4

The x term is -0.4x2.  Take half its coefficient (-0.2).
Square it (0.04) and add it to both sides.

Add '0.04' to each side of the equation.
-0.4x2 + 0.04 + x4 = -0.4 + 0.04

Reorder the terms:
0.04 + -0.4x2 + x4 = -0.4 + 0.04

Combine like terms: -0.4 + 0.04 = -0.36
0.04 + -0.4x2 + x4 = -0.36

Factor a perfect square on the left side:
(x2 + -0.2)(x2 + -0.2) = -0.36

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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